Greatest number which divides 285 and 1249
WebJul 30, 2024 · This is the Solution of Question From RD SHARMA book of CLASS 6 CHAPTER PLAYING WITH NUMBERS This Question is also available in R S AGGARWAL book of CLASS 6 ... WebApr 22, 2024 · Best answer The new numbers after subtracting remainders are: 285 - 9 = 276 1249 - 7 = 1242 Prime factors of 276 = 23 × 3 × 2 Prime factors of 1242 = 2 × 3 × 3 × 3 × 23 Therefore HCF of 276 and 1242 is: 2 × 3 × 23 = 138 Hence the greatest number which divides 285 and 1249 leaving remainder 9 and 7 respectively is 138 ← Prev …
Greatest number which divides 285 and 1249
Did you know?
WebPlease check your question accordingly. given number cannot be 1245 , rather its 1249. see the solved question ahead. Given numbers are 285 and 1249 and remainders are 9 … WebApr 9, 2024 · CERT In text burfis in ead the number ICF of 420 and m 3. Solution For thematics 8 members Tipe Very Short Anower Type Que the maxim INCERT Real Numbers Exercise 1.1 stack them a cast area of th rpose. CERT I.
WebPlease check your question accordingly. given number cannot be 1245 , rather its 1249. see the solved question ahead. Given numbers are 285 and 1249 and remainders are 9 and 7 respectively. Then new numbers after subtracting remainders are : 285 – 9 = 276. 1249 – 7 = 1242. The required number is HCF of 276 and 1242. WebApr 6, 2024 · Highest Common Factor (H.C.F) = 138. Therefore, the greatest number which divides 285 and 1249 leaving the remainder 9 and 7 respectively is 138, option …
WebTherefore, the greatest number which divides 285 and 1249 leaving the remainder 9 and 7 respectively is 138, option D). So, the correct answer Explain mathematic tasks. Mathematic is the study of topics such as quantity, structure, space, and change. ... WebJul 12, 2024 · Step-by-step explanation:[HCF of two or more numbers = product of the smallest power of each common prime factor involved in the numbers.] HCF of 276 and 1242 is 138. Hence, the required greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively is 138.
WebThe required greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively is 138. Was this answer helpful? upvote 0. Do my homework now. Find the …
WebOct 10, 2024 · To find: Here we have to find the value of the greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively. Solution: If the required number divide 285 and 1249 leaving remainders 9 and 7 respectively, then this means that number will divide 276 (285 − 9) and 1242 (1249 − 7) completely. share crappieWebFind the greatest number which divides 285 and 1249 leaving Answer: HCF of 276 and 1242 is 138. Hence, the required greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively is 138. Explain mathematic problems Mathematics is the study of numbers, shapes, and patterns. ... sharecrateWebWhat is the greatest number which divides 285 and 1249 leaving remainder 9 and 7 respectively? a) 134 b) 136 c) 138 d) 142 Correct answer is option 'C'. Can you explain this answer? Attach CancelAnswer to Question Answers Tanu … pool places in tillsonburgWebTherefore, the greatest number which divides 285 and 1249 leaving remainders 9 and 7 is 138. Related Questions. Find the largest number which divides 615 and Do my homework now. Find the greatest number which divides 285 and 1245 leaving Answer: HCF of 276 and 1242 is 138. Hence, the required greatest number which divides 285 … pool places in hopkinsville kyWebHence, the required greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively is 138. 424 Math Tutors 15 Years of experience Find the greatest … pool places in grand rapids miWebWhat is the greatest number which divides 285 and 1249. Answer: HCF of 276 and 1242 is 138. Hence, the required greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively is 138. Build brilliant future aspects Looking for a little help with your math homework? Check out our Math Homework Helper for tips and tricks on … sharecrazyWebJul 31, 2011 · Since on dividing 285 by the required number, the remainder is 9. ∴ 285 – 9 = 276 will be exactly divisible by the required number. Similarly, 1249 – 7 = 1242 will be also exactly divisible by the required number. pool places in jasper al